# Check if an array is sorted and rotated clockwise

Given an array of N distinct integers. The task is to write a program to check if this array is sorted and rotated clockwise. A sorted array is not considered as sorted and rotated, i.e., there should at least one rotation.

Examples:

```Input : arr[] = { 3, 4, 5, 1, 2 }
Output : YES
The above array is sorted and rotated.
Sorted array: {1, 2, 3, 4, 5}.
Rotating this sorted array clockwise
by 3 positions, we get: { 3, 4, 5, 1, 2}

Input: arr[] = {7, 9, 11, 12, 5}
Output: YES

Input: arr[] = {1, 2, 3}
Output: NO
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

• Find the minimum element in the array.
• Now, if the array is sorted and then rotated then all the elements before minimum element will be in increasing order and all elements after the minimum element will also be in increasing order.
• Check if all elements before minimum element are in increasing order.
• Check if all elements before minimum element are in increasing order.
• Check if the last element of the array is smaller than the element just before the minimum element.
• If all of the above three condition satisfies then print YES otherwise print NO.

Below is the implementation of the above idea:

## C++

 `// CPP program to check if an array is ` `// sorted and rotated clockwise ` `#include ` `#include ` ` `  `using` `namespace` `std; ` ` `  `// Function to check if an array is ` `// sorted and rotated clockwise ` `void` `checkIfSortRotated(``int` `arr[], ``int` `n) ` `{ ` `    ``int` `minEle = INT_MAX; ` `    ``int` `maxEle = INT_MIN; ` ` `  `    ``int` `minIndex = -1; ` ` `  `    ``// Find the minimum element ` `    ``// and it's index ` `    ``for` `(``int` `i = 0; i < n; i++) { ` `        ``if` `(arr[i] < minEle) { ` `            ``minEle = arr[i]; ` `            ``minIndex = i; ` `        ``} ` `    ``} ` ` `  `    ``int` `flag1 = 1; ` ` `  `    ``// Check if all elements before minIndex ` `    ``// are in increasing order ` `    ``for` `(``int` `i = 1; i < minIndex; i++) { ` `        ``if` `(arr[i] < arr[i - 1]) { ` `            ``flag1 = 0; ` `            ``break``; ` `        ``} ` `    ``} ` ` `  `    ``int` `flag2 = 1; ` ` `  `    ``// Check if all elements after minIndex ` `    ``// are in increasing order ` `    ``for` `(``int` `i = minIndex + 1; i < n; i++) { ` `        ``if` `(arr[i] < arr[i - 1]) { ` `            ``flag2 = 0; ` `            ``break``; ` `        ``} ` `    ``} ` ` `  `    ``// Check if last element of the array ` `    ``// is smaller than the element just ` `    ``// before the element at minIndex ` `    ``if` `(flag1 && flag2 && (arr[n - 1] < arr[minIndex - 1])) ` `        ``cout << ``"YES"``; ` `    ``else` `        ``cout << ``"NO"``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `arr[] = { 3, 4, 5, 1, 2 }; ` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr[0]); ` `    ``checkIfSortRotated(arr, n); ` `    ``return` `0; ` `} `

## Java

 `// Java program to check if an  ` `// array is sorted and rotated  ` `// clockwise  ` `import` `java.io.*; ` ` `  `class` `GFG ` `{ ` ` `  `// Function to check if an array is  ` `// sorted and rotated clockwise  ` `static` `void` `checkIfSortRotated(``int` `arr[],  ` `                               ``int` `n)  ` `{  ` `    ``int` `minEle = Integer.MAX_VALUE; ` `    ``int` `maxEle = Integer.MIN_VALUE; ` ` `  `    ``int` `minIndex = -``1``;  ` ` `  `    ``// Find the minimum element  ` `    ``// and it's index  ` `    ``for` `(``int` `i = ``0``; i < n; i++)  ` `    ``{  ` `        ``if` `(arr[i] < minEle)  ` `        ``{  ` `            ``minEle = arr[i];  ` `            ``minIndex = i;  ` `        ``}  ` `    ``}  ` ` `  `    ``boolean` `flag1 = ``true``;  ` ` `  `    ``// Check if all elements before  ` `    ``// minIndex are in increasing order  ` `    ``for` `(``int` `i = ``1``; i < minIndex; i++)  ` `    ``{  ` `        ``if` `(arr[i] < arr[i - ``1``])  ` `        ``{  ` `            ``flag1 = ``false``;  ` `            ``break``;  ` `        ``}  ` `    ``}  ` ` `  `    ``boolean` `flag2 = ``true``;  ` ` `  `    ``// Check if all elements after  ` `    ``// minIndex are in increasing order  ` `    ``for` `(``int` `i = minIndex + ``1``; i < n; i++) ` `    ``{  ` `        ``if` `(arr[i] < arr[i - ``1``])  ` `        ``{  ` `            ``flag2 = ``false``;  ` `            ``break``;  ` `        ``}  ` `    ``}  ` ` `  `    ``// Check if last element of the array  ` `    ``// is smaller than the element just  ` `    ``// before the element at minIndex  ` `    ``if` `(flag1 && flag2 && (arr[n - ``1``] < ` `                           ``arr[minIndex - ``1``]))  ` `        ``System.out.println(``"YES"``);  ` `    ``else` `        ``System.out.print(``"NO"``);  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `main (String[] args) ` `{ ` `    ``int` `arr[] = { ``3``, ``4``, ``5``, ``1``, ``2` `};  ` `     `  `    ``int` `n = arr.length; ` `     `  `    ``checkIfSortRotated(arr, n);  ` `} ` `} ` ` `  `// This code is contributed  ` `// by inder_verma. `

## Python3

 `# Python3 program to check if an  ` `# array is sorted and rotated clockwise ` `import` `sys ` ` `  `# Function to check if an array is ` `# sorted and rotated clockwise ` `def` `checkIfSortRotated(arr, n): ` `    ``minEle ``=` `sys.maxsize ` `    ``maxEle ``=` `-``sys.maxsize ``-` `1` `    ``minIndex ``=` `-``1` ` `  `    ``# Find the minimum element ` `    ``# and it's index ` `    ``for` `i ``in` `range``(n): ` `        ``if` `arr[i]< minEle: ` `            ``minEle ``=` `arr[i] ` `            ``minIndex ``=` `i ` `    ``flag1 ``=` `1` ` `  `    ``# Check if all elements before  ` `    ``# minIndex are in increasing order ` `    ``for` `i ``in` `range``(``1``, minIndex): ` `        ``if` `arr[i] < arr[i ``-` `1``]: ` `            ``flag1 ``=` `0` `            ``break` `    ``flag2 ``=` `2` ` `  `    ``# Check if all elements after  ` `    ``# minIndex are in increasing order ` `    ``for` `i ``in` `range``(minIndex ``+` `1``, n) : ` `        ``if` `arr[i] < arr[i ``-` `1``]: ` `            ``flag2 ``=` `0` `            ``break` ` `  `    ``# Check if last element of the array ` `    ``# is smaller than the element just ` `    ``# before the element at minIndex ` `    ``if` `(flag1 ``and` `flag2 ``and`  `        ``arr[n ``-` `1``] < arr[minIndex ``-` `1``]): ` `        ``print``(``"YES"``) ` `    ``else``: ` `        ``print``(``"NO"``) ` ` `  `# Driver code ` `arr ``=` `[``3``, ``4``, ``5``, ``1``, ``2` `] ` `n ``=` `len``(arr) ` `checkIfSortRotated(arr, n) ` ` `  `# This code is contributed  ` `# by Shrikant13 `

## C#

 `// C# program to check if an  ` `// array is sorted and rotated  ` `// clockwise  ` `using` `System; ` ` `  `class` `GFG ` `{ ` ` `  `// Function to check if an array is  ` `// sorted and rotated clockwise  ` `static` `void` `checkIfSortRotated(``int` `[]arr,  ` `                               ``int` `n)  ` `{  ` `    ``int` `minEle = ``int``.MaxValue; ` `    ``//int maxEle = int.MinValue; ` ` `  `    ``int` `minIndex = -1;  ` ` `  `    ``// Find the minimum element  ` `    ``// and it's index  ` `    ``for` `(``int` `i = 0; i < n; i++)  ` `    ``{  ` `        ``if` `(arr[i] < minEle)  ` `        ``{  ` `            ``minEle = arr[i];  ` `            ``minIndex = i;  ` `        ``}  ` `    ``}  ` ` `  `    ``bool` `flag1 = ``true``;  ` ` `  `    ``// Check if all elements before  ` `    ``// minIndex are in increasing order  ` `    ``for` `(``int` `i = 1; i < minIndex; i++)  ` `    ``{  ` `        ``if` `(arr[i] < arr[i - 1])  ` `        ``{  ` `            ``flag1 = ``false``;  ` `            ``break``;  ` `        ``}  ` `    ``}  ` ` `  `    ``bool` `flag2 = ``true``;  ` ` `  `    ``// Check if all elements after  ` `    ``// minIndex are in increasing order  ` `    ``for` `(``int` `i = minIndex + 1; i < n; i++) ` `    ``{  ` `        ``if` `(arr[i] < arr[i - 1])  ` `        ``{  ` `            ``flag2 = ``false``;  ` `            ``break``;  ` `        ``}  ` `    ``}  ` ` `  `    ``// Check if last element of the array  ` `    ``// is smaller than the element just  ` `    ``// before the element at minIndex  ` `    ``if` `(flag1 && flag2 && (arr[n - 1] < ` `                           ``arr[minIndex - 1]))  ` `        ``Console.WriteLine(``"YES"``);  ` `    ``else` `        ``Console.WriteLine(``"NO"``);  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `Main () ` `{ ` `    ``int` `[]arr = { 3, 4, 5, 1, 2 };  ` `     `  `    ``int` `n = arr.Length; ` `     `  `    ``checkIfSortRotated(arr, n);  ` `} ` `} ` ` `  `// This code is contributed  ` `// by inder_verma. `

## PHP

 ` `

Output:

```YES
```

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