Check if two trees have same structure

Given two binary trees. The task is to write a program to check if the two trees are identical in structure.

In the above figure both of the trees, Tree1 and Tree2 are identical in structure. That is, they have the same structure.

Note: This problem is different from Check if two trees are identical as here we need to compare only the structures of the two trees and not the values at their nodes.

The idea is to traverse both trees simultaneously following the same paths and keep checking if a node exists for both the trees or not.


  1. If both trees are empty then return 1.
  2. Else If both trees are non-empty:
    • Check left subtrees recursively i.e., call isSameStructure(tree1->left_subtree, tree2->left_subtree)
    • Check right subtrees recursively i.e., call isSameStructure(tree1->right_subtree, tree2->right_subtree)
    • If the value returned in above two steps are true then return 1.
  3. Else return 0 (one is empty and other is not).

Below is the implementation of above algorithm:





// C++ program to check if two trees have 
// same structure
#include <iostream>
using namespace std;
// A binary tree node has data, pointer to left child
// and a pointer to right child 
struct Node
    int data;
    struct Node* left;
    struct Node* right;
// Helper function that allocates a new node with the
// given data and NULL left and right pointers. 
Node* newNode(int data)
    Node* node = new Node;
    node->data = data;
    node->left = NULL;
    node->right = NULL;
// Function to check if two trees have same 
// structure
int isSameStructure(Node* a, Node* b)
    // 1. both empty 
    if (a==NULL && b==NULL)
        return 1;
    // 2. both non-empty -> compare them 
    if (a!=NULL && b!=NULL)
            isSameStructure(a->left, b->left) &&
            isSameStructure(a->right, b->right)
    // 3. one empty, one not -> false 
    return 0;
// Driver code
int main()
    Node *root1 = newNode(10);
    Node *root2 = newNode(100);
    root1->left = newNode(7);
    root1->right = newNode(15);
    root1->left->left = newNode(4);
    root1->left->right = newNode(9); 
    root1->right->right = newNode(20);
    root2->left = newNode(70);
    root2->right = newNode(150);
    root2->left->left = newNode(40);
    root2->left->right = newNode(90); 
    root2->right->right = newNode(200);
    if (isSameStructure(root1, root2))
        printf("Both trees have same structure");
        printf("Trees do not have same structure");
    return 0;



Both trees have same structure

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