Given an integer N, the task is to find the number of trailing zeroes in the base 16 representation of the factorial of N.
Input: N = 6
6! = 720 (base 10) = 2D0 (base 16)
Input: N = 100
- Number of trailing zeroes would be the highest power of 16 in the factorial of N in base 10.
- We know that 16 = 24. So, the highest power of 16 is equal to the highest power 2 in the factorial of N divided by 4.
- To calculate the highest power of 2 in N!, we can use Legendre’s Formula.
Below is the implementation of the above approach:
- Number of trailing zeroes in base B representation of N!
- Count trailing zeroes in factorial of a number
- Smallest number with at least n trailing zeroes in factorial
- Trailing number of 0s in product of two factorials
- Find the smallest number X such that X! contains at least Y trailing zeros.
- Next greater number than N with exactly one bit different in binary representation of N
- Number of mismatching bits in the binary representation of two integers
- Sum of decimal equivalent of all possible pairs of Binary representation of a Number
- Find consecutive 1s of length >= n in binary representation of a number
- Count number of triplets with product equal to given number with duplicates allowed
- Count number of triplets with product equal to given number with duplicates allowed | Set-2
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- Maximum number of contiguous array elements with same number of set bits
- Number of steps required to convert a binary number to one
- Check whether all the rotations of a given number is greater than or equal to the given number or not
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