Given n nodes of a tree and their connections, print Subtree nodes of every node.
Subtree of a node is defined as a tree which is a child of a node. The name emphasizes that everything which is a descendant of a tree node is a tree too, and is a subset of the larger tree.
Input: N = 5 0 1 1 2 0 3 3 4 Output: Subtree of node 0 is 1 2 3 4 Subtree of node 1 is 2 Subtree of node 3 is 4 Input: N = 7 0 1 1 2 2 3 0 4 4 5 4 6 Output: Subtree of node 0 is 1 2 3 4 5 6 Subtree of node 1 is 2 3 Subtree of node 4 is 5 6
Approach: Do DFS traversal for every node and print all the nodes which are reachable from a particular node.
Explanation of below code:
- When function dfs(0, 0) is called, start = 0, dfs_order.push_back(0), visited = 1 to keep track of dfs order.
- Now, consider adjacency list (adj) as considering directional path elements connected to node 0 will be in adjacency list corresponding to node 0.
- Now, recursively call dfs function till all elements traversed of adj.
- Now, dfs(1, 2) is called, Now start = 1, dfs_order.push_back(1), visited = 1 after adj elements is traversed.
- Now adj  is traversed which contain only node 2 when adj is traversed it contains no element, it will break and end=2.
- Similarly, all nodes traversed and store dfs_order in array to find subtree of nodes.
subtree of node 0 is 1 4 7 8 5 2 6 9 3 subtree of node 1 is 4 7 8 5 subtree of node 2 is 6 9 subtree of node 4 is 7 8 subtree of node 6 is 9
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